MDCAT Physics MCQ #3681

A physicist calculates the vector product of A = 2i and B = 3j. What is the magnitude of the resulting vector A x B?

MDCAT Physics MCQ #3681

  1. Question 1

    Q1. A physicist calculates the vector product of A = 2i and B = 3j. What is the magnitude of the resulting vector A x B?

    • A) 0
    • B) 1
    • C) 6
    • D) 5

    Answer: 6

    Explanation: The magnitude of the cross product (2i x 3j) is 6k, which has a magnitude of 6. Option D fails by adding the magnitudes.