A 10 N force is applied at the end of a 2 m long lever arm at an angle of 30 degrees to the arm. Find the torque.
Q1. A 10 N force is applied at the end of a 2 m long lever arm at an angle of 30 degrees to the arm. Find the torque.
Answer: 10.0 Nm
Explanation: Torque is rF sin(theta), so 2m * 10N * sin(30) = 10 Nm. Option A fails because it uses cosine instead of sine.