MDCAT Physics MCQ #3690

A force F = 2i + 3j acts on a body, moving it from (1, 1) to (4, 5). Calculate the work done by this force.

MDCAT Physics MCQ #3690

  1. Question 1

    Q1. A force F = 2i + 3j acts on a body, moving it from (1, 1) to (4, 5). Calculate the work done by this force.

    • A) 23 J
    • B) 15 J
    • C) 18 J
    • D) 12 J

    Answer: 18 J

    Explanation: Displacement d is (4-1)i + (5-1)j = 3i + 4j. Work = F dot d = (2)(3) + (3)(4) = 18 J. Option D is incorrect.