A 50 cm long rod is pivoted at one end. A force of 10 N is applied at the other end at 30 degrees. What is the torque?
Q1. A 50 cm long rod is pivoted at one end. A force of 10 N is applied at the other end at 30 degrees. What is the torque?
Answer: 2.5 Nm
Explanation: Torque is r multiplied by the perpendicular component of F. Option D fails because it uses the wrong trigonometric function for the lever arm.