MDCAT Physics MCQ #3705

A force F = 3i + 4j Newtons displaces a body by d = 2i + 3j meters. What is the work done by the force?

MDCAT Physics MCQ #3705

  1. Question 1

    Q1. A force F = 3i + 4j Newtons displaces a body by d = 2i + 3j meters. What is the work done by the force?

    • A) 12 J
    • B) 7 J
    • C) 24 J
    • D) 18 J

    Answer: 18 J

    Explanation: Work is the dot product F.d = (3*2) + (4*3) = 18. Option B is incorrect because it adds components without multiplying.