MDCAT Physics MCQ #373

A chemist measures the energy required for an electron to jump from the third orbit to the fourth orbit in a hydrogen atom.

MDCAT Physics MCQ #373

  1. Question 1

    Q1. A chemist measures the energy required for an electron to jump from the third orbit to the fourth orbit in a hydrogen atom.

    • A) ΔE = Δk = 13.6eV
    • B) ΔE = (13.6 * (3^2) - 13.6 * (4^2)) eV
    • C) ΔE = (13.6 * (4^2) - 13.6 * (3^2)) eV
    • D) ΔE = (13.6 * (4^2)) eV

    Answer: ΔE = (13.6 * (3^2) - 13.6 * (4^2)) eV

    Explanation: The correct formula calculates the energy difference between the two orbits, while option B calculates the energy required for the electron to jump to infinity.