MDCAT Physics MCQ #377

In the Balmer series, the energy levels of the hydrogen atom are given by the formula E_n = -13.6 * (1/n^2) eV. Which of the following transitions has the lowest energy?

MDCAT Physics MCQ #377

  1. Question 1

    Q1. In the Balmer series, the energy levels of the hydrogen atom are given by the formula E_n = -13.6 * (1/n^2) eV. Which of the following transitions has the lowest energy?

    • A) n = 2 to n = 3
    • B) n = 3 to n = 4
    • C) n = 4 to n = 5
    • D) n = 5 to n = 6

    Answer: n = 3 to n = 4

    Explanation: The transition from n = 3 to n = 4 has the lowest energy as it involves the smallest energy difference.