MDCAT Physics MCQ #378

A physicist wants to calculate the energy required for an electron to jump from the fifth orbit to the sixth orbit in a hydrogen atom.

MDCAT Physics MCQ #378

  1. Question 1

    Q1. A physicist wants to calculate the energy required for an electron to jump from the fifth orbit to the sixth orbit in a hydrogen atom.

    • A) ΔE = (13.6 * (5^2)) - (13.6 * (6^2)) eV
    • B) ΔE = (13.6 * (6^2)) - (13.6 * (5^2)) eV
    • C) ΔE = (13.6 * (5^2)) - (13.6 * (5^2)) eV
    • D) ΔE = (13.6 * (6^2)) - (13.6 * (6^2)) eV

    Answer: ΔE = (13.6 * (6^2)) - (13.6 * (5^2)) eV

    Explanation: The correct formula calculates the energy difference between the two orbits, while option B calculates the energy required for the electron to jump to infinity.