MDCAT Physics MCQ #3974

A string of length 1.5 m is fixed at both ends and vibrates at a frequency of 120 Hz in its fundamental mode. Calculate the speed of the wave in the string.

MDCAT Physics MCQ #3974

  1. Question 1

    Q1. A string of length 1.5 m is fixed at both ends and vibrates at a frequency of 120 Hz in its fundamental mode. Calculate the speed of the wave in the string.

    • A) 180 m/s
    • B) 240 m/s
    • C) 360 m/s
    • D) 480 m/s

    Answer: 360 m/s

    Explanation: For fundamental mode, wavelength = 2 * length = 3 m. Speed = frequency * wavelength = 120 Hz * 3 m = 360 m/s. Option B is incorrect due to wrong wavelength consideration.