MDCAT Physics MCQ #3977

A tuning fork vibrating at 256 Hz is near a closed pipe of length 0.33 m. The pipe is in resonance. What is the speed of sound?

MDCAT Physics MCQ #3977

  1. Question 1

    Q1. A tuning fork vibrating at 256 Hz is near a closed pipe of length 0.33 m. The pipe is in resonance. What is the speed of sound?

    • A) 330 m/s
    • B) 336 m/s
    • C) 340 m/s
    • D) 344 m/s

    Answer: 336 m/s

    Explanation: For a closed pipe, the fundamental frequency corresponds to wavelength = 4 * length = 1.32 m. Speed = frequency * wavelength = 256 Hz * 1.32 m = 338 m/s, closest to 336 m/s considering rounding. Option A is incorrect due to slight miscalculation.