MDCAT Physics MCQ #4392

A force of 10 N acts on a body, displacing it by 2 m in the direction of the force. What is the work done?

MDCAT Physics MCQ #4392

  1. Question 1

    Q1. A force of 10 N acts on a body, displacing it by 2 m in the direction of the force. What is the work done?

    • A) 5 J
    • B) 10 J
    • C) 20 J
    • D) 40 J

    Answer: 20 J

    Explanation: Work done is calculated as force times displacement in the direction of the force, so 10 N * 2 m = 20 J.