A force of 20 N acts on a body at an angle of 60° to its direction of motion. What is the work done in moving the body 10 m?
Q1. A force of 20 N acts on a body at an angle of 60° to its direction of motion. What is the work done in moving the body 10 m?
Answer: 100 J
Explanation: Work done = F × d × cos(θ) = 20 N × 10 m × cos(60°) = 100 J. Option A fails due to incorrect angle application.