A spring with a spring constant of 500 N/m is compressed by 0.2 m. What is the elastic potential energy stored?
Q1. A spring with a spring constant of 500 N/m is compressed by 0.2 m. What is the elastic potential energy stored?
Answer: 10 J
Explanation: Elastic PE = ½kx² = ½ × 500 N/m × (0.2 m)² = 10 J. Option A fails due to incorrect formula application.