A 2 kg object is dropped from a height of 10 m. What is its kinetic energy just before hitting the ground? (g = 10 m/s²)
Q1. A 2 kg object is dropped from a height of 10 m. What is its kinetic energy just before hitting the ground? (g = 10 m/s²)
Answer: 200 J
Explanation: KE = mgh = 2 kg × 10 m/s² × 10 m = 200 J. Option A fails due to miscalculation.