A 2 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (g = 10 m/s²)
Q1. A 2 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (g = 10 m/s²)
Answer: 10 m/s
Explanation: mgh = ½mv²; v = √(2gh) = √(2 × 10 m/s² × 5 m) = 10 m/s. Option B fails due to miscalculation.