MDCAT Physics MCQ #4433

A force of 10 N acts on a body, displacing it 5 m at an angle of 60°. What is the work done?

MDCAT Physics MCQ #4433

  1. Question 1

    Q1. A force of 10 N acts on a body, displacing it 5 m at an angle of 60°. What is the work done?

    • A) 25 J
    • B) 43.3 J
    • C) 50 J
    • D) 21.65 J

    Answer: 25 J

    Explanation: Work done = F * d * cos(θ) = 10 N * 5 m * cos(60°) = 25 J. Option B is incorrect due to miscalculation.