MDCAT Physics MCQ #4438

A 50 N force is applied at an angle of 30° to the horizontal, displacing a body 10 m horizontally. What is the work done?

MDCAT Physics MCQ #4438

  1. Question 1

    Q1. A 50 N force is applied at an angle of 30° to the horizontal, displacing a body 10 m horizontally. What is the work done?

    • A) 433 J
    • B) 500 J
    • C) 250 J
    • D) 375 J

    Answer: 433 J

    Explanation: Work done = F * d * cos(θ) = 50 N * 10 m * cos(30°) = 433 J. Option B is incorrect due to miscalculation.