A force F = (2x + 3) N acts on a body, displacing it from x = 0 to x = 2 m. What is the work done?
Q1. A force F = (2x + 3) N acts on a body, displacing it from x = 0 to x = 2 m. What is the work done?
Answer: 10 J
Explanation: Work done = ∫F dx = ∫(2x + 3) dx from 0 to 2 = [x^2 + 3x] from 0 to 2 = 10 J. Option B is incorrect due to miscalculation.