A spring is compressed by 0.2 m, storing 4 J of energy. What is its spring constant?
Q1. A spring is compressed by 0.2 m, storing 4 J of energy. What is its spring constant?
Answer: 200 N/m
Explanation: Elastic potential energy = 0.5 * k * x^2. Rearranging, k = 2 * energy / x^2 = 2 * 4 J / (0.2 m)^2 = 200 N/m. Option B is incorrect due to miscalculation.