A battery has an emf of 12 V and an internal resistance of 0.5 ohm. When connected to an external resistance of 2.5 ohm, what is the current?
Q1. A battery has an emf of 12 V and an internal resistance of 0.5 ohm. When connected to an external resistance of 2.5 ohm, what is the current?
Answer: 4 A
Explanation: Using the formula I = E/(R + r), we get I = 12/(2.5 + 0.5) = 4 A. Option A is incorrect because it miscalculates the total resistance.