A 5 ohm resistor is connected to a 10V battery. What is the energy dissipated in 2 seconds?
Q1. A 5 ohm resistor is connected to a 10V battery. What is the energy dissipated in 2 seconds?
Answer: 40 J
Explanation: P = V^2/R = 10^2/5 = 20 W, E = P*t = 20*2 = 40 J.