A capacitor of 100 μF is connected to an AC source of 50 Hz. What is its capacitive reactance?
Q1. A capacitor of 100 μF is connected to an AC source of 50 Hz. What is its capacitive reactance?
Answer: 31.83 ohms
Explanation: X_C = 1/(2πfC) = 1/(2 * 3.14 * 50 * 100 * 10^(-6)) = 31.83 ohms. Option B is incorrect due to wrong calculation.