A 2-turn coil has a radius of 0.05 m. The magnetic field around it is 5 × 10^-3 T. What is the magnitude of the induced voltage?
Q1. A 2-turn coil has a radius of 0.05 m. The magnetic field around it is 5 × 10^-3 T. What is the magnitude of the induced voltage?
Answer: 1 × 10^-4 V
Explanation: Using Faraday's law of induction. Induced voltage is 2 * pi * r^2 * B * N * (dΦ/dt) = 3.14 * 0.05^2 * 5e-3 * 2 * 1e-4 s^-1.