A wire 0.5 m long carrying a current of 8 A is perpendicular to a 2 T magnetic field. What is the force on the wire?
Q1. A wire 0.5 m long carrying a current of 8 A is perpendicular to a 2 T magnetic field. What is the force on the wire?
Answer: 8 N
Explanation: Force = ILB = 8 x 0.5 x 2 = 8 N. Option B is wrong because it incorrectly calculates the force.