A solenoid with 500 turns per meter carries a current of 3 A. What is the magnetic field inside the solenoid?
Q1. A solenoid with 500 turns per meter carries a current of 3 A. What is the magnetic field inside the solenoid?
Answer: 1.88 mT
Explanation: B = μ₀nI = 4π x 10⁻⁷ x 500 x 3 = 1.88 mT. Option D is wrong due to incorrect μ₀ value.