Two parallel wires 0.2 m apart carry currents of 5 A and 8 A in the same direction. What is the force per unit length between the wires?
Q1. Two parallel wires 0.2 m apart carry currents of 5 A and 8 A in the same direction. What is the force per unit length between the wires?
Answer: 4 x 10⁻⁵ N/m
Explanation: F/L = (μ₀I₁I₂)/(2πd) = (4π x 10⁻⁷ x 5 x 8)/(2π x 0.2) = 4 x 10⁻⁵ N/m. Option C is wrong due to incorrect calculation.