A current of 2 A flows through a coil of 500 turns and induces a magnetic flux of 0.01 Wb. What is the self-inductance of the coil?
Q1. A current of 2 A flows through a coil of 500 turns and induces a magnetic flux of 0.01 Wb. What is the self-inductance of the coil?
Answer: 2.5 H
Explanation: L = NΦ/I = 500 x 0.01/2 = 2.5 H. Option B is wrong due to miscalculation.