OTS Revenue Department Posts Mathematics Number Theory — Set 3

Number Theory MCQs set 3 for OTS Revenue Department Posts Mathematics — 20 solved questions.

OTS Revenue Department Posts Mathematics Number Theory — Set 3

  1. Question 1

    Q1. Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?

    • A) 101
    • B) 103
    • C) 107
    • D) 113

    Answer: 103

    Explanation: The required number divides 4242−2903 = 1339. Factorising 1339 = 13 × 103; the three-digit factor is 103.

  2. Question 2

    Q2. The least number of four digits which is divisible by 4, 6, 8 and 10 is_________?

    • A) 1080
    • B) 1085
    • C) 1075
    • D) 1095

    Answer: 1080

    Explanation: LCM of 4, 6, 8, 10 = 120; smallest four-digit multiple of 120 = 120 × 9 = 1080.

  3. Question 3

    Q3. The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is_________?

    • A) 123
    • B) 127
    • C) 235
    • D) 305

    Answer: 127

    Explanation: Find HCF of (1657−6)=1651 and (2037−5)=2032. Applying the Euclidean algorithm gives HCF=127.

  4. Question 4

    Q4. What is the smallest number, which when divided by 3,8 and 15 leaves the remainder 1,6,13 respectively?

    • A) 121
    • B) 242
    • C) 118
    • D) 239

    Answer: 118

    Explanation: The deficit (divisor−remainder) is constant at 2 for each divisor. LCM(3,8,15) = 120. Answer = 120−2 = 118.

  5. Question 5

    Q5. In a division, problem the divisor is 4 times the quotient and 3 times the remainder, if remained is 4, then the dividend is?

    • A) 12
    • B) 40
    • C) 42
    • D) 44

    Answer: 40

    Explanation: Remainder = 4, divisor = 3×4 = 12, quotient = 12/4 = 3; dividend = 12×3 + 4 = 40.

  6. Question 6

    Q6. How many two-digit numbers are there that are divisible by 11?

    • A) 7
    • B) 8
    • C) 9
    • D) 11

    Answer: 9

    Explanation: Two-digit multiples of 11 are: 11, 22, 33, 44, 55, 66, 77, 88, 99 - a total of 9 numbers.

  7. Question 7

    Q7. Which one of the following is not a prime number?

    • A) 11
    • B) 61
    • C) 91
    • D) 31

    Answer: 91

    Explanation: 91 = 7 × 13, so it has factors other than 1 and itself, making it a composite number, not prime.

  8. Question 8

    Q8. The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 13 and 14. The larger of the two numbers is___________?

    • A) 276
    • B) 299
    • C) 322
    • D) 345

    Answer: 322

    Explanation: The two numbers are 23 × 13 = 299 and 23 × 14 = 322; the larger is 322.

  9. Question 9

    Q9. Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder?

    • A) 210
    • B) 119
    • C) 126
    • D) 154

    Answer: 119

    Explanation: LCM(2,3,4,5,6) = 60; numbers of the form 60k−1 that are divisible by 7: 60×2−1 = 119 = 7×17.

  10. Question 10

    Q10. Find the lowest common multiple of 24, 36 and 40. LCM

    • A) 120
    • B) 240
    • C) 360
    • D) 480

    Answer: 360

    Explanation: 24=2³×3, 36=2²×3², 40=2³×5. LCM = 2³×3²×5 = 360. Show the calculation clearly when solving similar quantitative items.

  11. Question 11

    Q11. The least number which, when increased by 3, is completely divisible by 8, 12 and 18 is_______?

    • A) 71
    • B) 70
    • C) 69
    • D) 68

    Answer: 69

    Explanation: LCM(8, 12, 18) = 72; the required number is 72 − 3 = 69, which when increased by 3 equals 72.

  12. Question 12

    Q12. The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

    • A) 3
    • B) 13
    • C) 23
    • D) 33

    Answer: 23

    Explanation: LCM(5, 6, 4, 3) = 60; 2497 ÷ 60 leaves remainder 37; adding 60 − 37 = 23 makes 2520, which is divisible by all four numbers.

  13. Question 13

    Q13. What are Prime Numbers?

    • A) Which can be divided by Odd Numbers
    • B) Which can be divided by Even Numbers
    • C) Which can be divided by Number 1 & by itself Number
    • D) Which can be divided by any Number

    Answer: Which can be divided by Number 1 & by itself Number

    Explanation: A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.

  14. Question 14

    Q14. Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively?

    • A) 143
    • B) 169
    • C) 260
    • D) 221

    Answer: 143

    Explanation: LCM(6,8,12) = 24; required number = 24k-1 and divisible by 13. Testing: 24×6-1 = 143 = 11×13. So 143 is the answer.

  15. Question 15

    Q15. Find the least square number which is divisible by 10, 12, 15 and 18?

    • A) 1600
    • B) 900
    • C) 3600
    • D) 2500

    Answer: 900

    Explanation: LCM(10,12,15,18) = 180 = 2²×3²×5. To make it a perfect square, multiply by 5 to get 900 = 2²×3²×5².

  16. Question 16

    Q16. Factorize 3x²y² - 14xy + 16:

    • A) (xy-2)(3xy-8)
    • B) (xy-2)(3xy+8)
    • C) (xy+2)(3xy-8)
    • D) None of these

    Answer: (xy-2)(3xy-8)

    Explanation: The correct value is (xy-2)(3xy-8). Apply the formula or arithmetic step shown in the question and

  17. Question 17

    Q17. The product of two digits number is 2160 and their HCF is 12. The numbers are________?

    • A) (36,60)
    • B) -12180
    • C) (96,25)
    • D) (72,30)

    Answer: (36,60)

    Explanation: HCF=12, so numbers = 12a and 12b where a,b are co-prime. 144ab=2160 → ab=15. Co-prime pairs: (1,15) and (3,5). Only 2-digit pair is (36, 60).

  18. Question 18

    Q18. Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case?

    • A) 16
    • B) 17
    • C) 18
    • D) 19

    Answer: 16

    Explanation: Subtracting the remainder 3 from each: 16, 80, 64; GCF(16,80,64) = 16.

  19. Question 19

    Q19. The least square number which is divisible by 8, 12 and 18 is________?

    • A) 100
    • B) 121
    • C) 64
    • D) 144

    Answer: 144

    Explanation: LCM(8,12,18) = 72 = 2³×3²; the smallest perfect square multiple is 144 = 2⁴×3² = 12².

  20. Question 20

    Q20. Find the least number of five digits which is exactly divisible by 12, 15 and 18?

    • A) 1080
    • B) 10080
    • C) 10025
    • D) 11080

    Answer: 10080

    Explanation: LCM(12, 15, 18) = 180. The smallest 5-digit multiple of 180 is 180×56 = 10080.

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Level 1

Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?