Work & Energy MCQs set 2 for Air University Entry Test Physics — 20 solved questions.
Q1. A force of 5 N acts on a body, displacing it by 2 m. What is the work done?
Answer: 10 J
Explanation: Work done = F * d = 5 * 2 = 10 J, using the formula for work done.
Q2. A body of mass 1 kg is lifted to a height of 2 m. What is the potential energy gained?
Answer: 19.6 J
Explanation: Potential energy = mgh = 1 * 9.8 * 2 = 19.6 J, using the formula for potential energy.
Q3. A spring of spring constant 100 N/m is compressed by 0.1 m. What is the energy stored?
Answer: 0.5 J
Explanation: Energy stored = 1/2 kx² = 1/2 * 100 * 0.1² = 0.5 J, using the formula for energy stored in a spring.
Q4. A body is moving in a circular path. What is the work done by the centripetal force?
Answer: Zero
Explanation: Work done by centripetal force is zero as it is perpendicular to displacement, using the concept of work done.
Q5. A 5 kg block is moving with 2 m/s velocity. What is its momentum?
Answer: 10 kg m/s
Explanation: Momentum = mv = 5 * 2 = 10 kg m/s, using the formula for momentum.
Q6. A body of mass 2 kg is moving with 3 m/s velocity. What is its kinetic energy?
Answer: 9 J
Explanation: Kinetic energy = 1/2 mv² = 1/2 * 2 * 3² = 9 J, using the formula for kinetic energy.
Q7. A spring is stretched by 0.2 m. If its spring constant is 50 N/m, what is the energy stored?
Answer: 1 J
Explanation: Energy stored = 1/2 kx² = 1/2 * 50 * 0.2² = 1 J, using the formula for energy stored in a spring.
Q8. A body is lifted to a height of 5 m. If its mass is 3 kg, what is the potential energy gained?
Answer: 147 J
Explanation: Potential energy = mgh = 3 * 9.8 * 5 = 147 J, using the formula for potential energy.
Q9. A force of 20 N acts on a body, displacing it by 3 m. What is the work done?
Answer: 60 J
Explanation: Work done = F * d = 20 * 3 = 60 J, using the formula for work done.
Q10. A body of mass 4 kg is moving with 2 m/s velocity. What is its kinetic energy?
Answer: 8 J
Explanation: Kinetic energy = 1/2 mv² = 1/2 * 4 * 2² = 8 J, using the formula for kinetic energy.
Q11. A spring of spring constant 200 N/m is compressed by 0.2 m. What is the energy stored?
Answer: 4 J
Explanation: Energy stored = 1/2 kx² = 1/2 * 200 * 0.2² = 4 J, using the formula for energy stored in a spring.
Q12. A body is moving in a circular path of radius 2 m. If its mass is 1 kg and velocity is 4 m/s, what is its kinetic energy?
Answer: 8 J
Explanation: Kinetic energy = 1/2 mv² = 1/2 * 1 * 4² = 8 J, using the formula for kinetic energy.
Q13. A force of 15 N acts on a body for 3 s. What is the impulse?
Answer: 45 Ns
Explanation: Impulse = F * t = 15 * 3 = 45 Ns, using the formula for impulse.
Q14. A body of mass 2 kg is lifted to a height of 4 m. What is the potential energy gained?
Answer: 78.4 J
Explanation: Potential energy = mgh = 2 * 9.8 * 4 = 78.4 J, using the formula for potential energy.
Q15. A spring is stretched by 0.1 m. If its spring constant is 100 N/m, what is the energy stored?
Answer: 0.5 J
Explanation: Energy stored = 1/2 kx² = 1/2 * 100 * 0.1² = 0.5 J, using the formula for energy stored in a spring.
Q16. A body is moving with 5 m/s velocity. If its mass is 3 kg, what is its kinetic energy?
Answer: 37.5 J
Explanation: Kinetic energy = 1/2 mv² = 1/2 * 3 * 5² = 37.5 J, using the formula for kinetic energy.
Q17. A force of 25 N acts on a body, displacing it by 2 m. What is the work done?
Answer: 50 J
Explanation: Work done = F * d = 25 * 2 = 50 J, using the formula for work done.
Q18. A body of mass 1 kg is moving with 6 m/s velocity. What is its kinetic energy?
Answer: 18 J
Explanation: Kinetic energy = 1/2 mv² = 1/2 * 1 * 6² = 18 J, using the formula for kinetic energy.
Q19. A force of 10 N acts on a body, displacing it by 5 m. What is the work done?
Answer: 50 J
Explanation: Work done = F * d = 10 * 5 = 50 J, using the formula for work done.
Q20. A 5 kg block is lifted to a height of 2 m. What is the potential energy gained?
Answer: 98 J
Explanation: Potential energy = mgh = 5 * 9.8 * 2 = 98 J, using the formula for potential energy.